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JEE Main 2022 (25 Jun, Shift 2) · Centripetal Acceleration & Force

Centripetal Acceleration & Force question from JEE Main 2022 (25 Jun, Shift 2)

Q27JEE Main 2022 · 25 JUN · SHIFT 2Medium

Centripetal Acceleration & Force

For a particle in uniform circular motion, the accelerationa⃗\vec{a}at any point P(R, θ\theta) on the circular path of radius R is (when θ\theta is measured from the positive x-axis and v is uniform speed):

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Answer: (c)

  1. In UCM the acceleration has magnitude v2R\frac{v^2}{R} and points from P towards the centre.
  2. Position unit vector of P is cos⁡θ i^+sin⁡θ j^\cos\theta\,\hat{i} + \sin\theta\,\hat{j}; the acceleration is opposite to it.
  3. a⃗=−v2Rcos⁡θ i^−v2Rsin⁡θ j^\vec a = -\frac{v^2}{R}\cos\theta\,\hat{i} - \frac{v^2}{R}\sin\theta\,\hat{j}
  4. So the answer is (c).
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