Student Login

Home›Chapters›Oscillations PYQs›Energy in SHM›Question 7

MHT CET 2026 (16 Apr, Shift 1) · Energy in SHM

Energy in SHM question from MHT CET 2026 (16 Apr, Shift 1)

Q7MHT CET 2026 · 16 APR · SHIFT 1Easy

Energy in SHM

For a particle P performing S.H.M., when displacement is 'x', potential energy and restoring force acting on it is denoted by 'E' and 'F' respectively. The relation between x, E and F is

Show answer and solution

Answer: (b)

$E = \dfrac{1}{2}kx^2$ and $F = -kx$ .
$\dfrac{2E}{F} = \dfrac{kx^2}{-kx} = -x$
$\dfrac{2E}{F} + x = 0$
So the answer is (b).

Report a mistake

More questions on Energy in SHM

The amplitude of a particle executing SHM is 3 cm. The displacement at which its kinetic…MHT CET 2026 (13 Apr, Shift 2)
For a simple pendulum, having time period T, the variation of kinetic energy (K.E.) with…NEET 2026
A linear harmonic oscillator of force constant 2 × 10⁶ N/m has amplitude 0.01 m. ItsMHT CET 2026 (19 May, Shift 2)
A mass 0.4 kg performs S.H.M. with a frequency 16/π Hz. At a certain displacement it has…MHT CET 2026 (11 Apr, Shift 2)
Maximum kinetic energy of a particle of mass 1 kg in S.H.M. is 8 J and the time period is…MHT CET 2026 (14 May, Shift 1)
A particle of mass ' m ' is executing S.H.M. about the origin on x-axis with frequency…MHT CET 2026 (18 Apr, Shift 2)
A block is fastened to a horizontal spring. The block is pulled to a distance x = 10 cm…MHT CET 2026 (13 Apr, Shift 2)
A particle starts oscillating simple harmonically from its equilibrium position with time…MHT CET 2026 (14 May, Shift 2)