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MHT CET 2025 (19 Apr, Shift 2) · Velocity & Acceleration in SHM

Velocity & Acceleration in SHM question from MHT CET 2025 (19 Apr, Shift 2)

Q18MHT CET 2025 · 19 APR · SHIFT 2Easy

Velocity & Acceleration in SHM

For a particle performing S.H.M. the displacement - time graph is shown.

For that particle the force - time graph is correctly shown in graph

Show answer and solution

Answer: (c)

The graph starts at $y = 0$ and rises, so $y = A\sin\omega t$ .
Restoring force $F = -ky = -kA\sin\omega t$ .
So $F$ starts at zero and first goes negative, then positive: an inverted sine curve.
So the answer is (c).

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