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JEE Main 2023 (10 Apr, Shift 2) · Periodic Motion & SHM Basics

Periodic Motion & SHM Basics question from JEE Main 2023 (10 Apr, Shift 2)

Q33JEE Main 2023 · 10 APR · SHIFT 2Medium

Periodic Motion & SHM Basics

For a periodic motion represented by the equation

y=sin⁡ωt+cos⁡ωty = \sin \omega t + \cos \omega t

the amplitude of the motion is

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Answer: (b)

  1. For asin⁡ωt+bcos⁡ωta\sin\omega t + b\cos\omega t, amplitude =a2+b2= \sqrt{a^2 + b^2}.
  2. 12+12=2\sqrt{1^2 + 1^2} = \sqrt{2}, i.e. y=2sin⁡(ωt+π/4)y = \sqrt{2}\sin(\omega t + \pi/4).
  3. So the answer is (b) 2\sqrt{2}.
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