For a projectile, the maximum height and horizontal range are same. The angle of projection ' θ ' of the projectile is (a) tan ⁻¹(1/4) (b) tan ⁻¹(2) (c) tan ⁻¹(1/4) (d) tan ⁻¹(4)

Answer: (d). R = 4Hcot θ (from R/H = (4)/(tan θ)). R = H ⇒ tan θ = 4 So the answer is (d) tan ⁻¹(4).

For a projectile, the maximum height and horizontal range are same… | MHT CET 2024 (4 May, Shift 1)

Q11MHT CET 2024 · 4 MAY · SHIFT 1Easy

Time of Flight, Maximum Height & Range

For a projectile, the maximum height and horizontal range are same. The angle of projection ' $\theta$ ' of the projectile is

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Answer: (d)

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