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MHT CET 2024 (11 May, Shift 2) · Satellite Energy & Weightlessness

Satellite Energy & Weightlessness question from MHT CET 2024 (11 May, Shift 2)

Q6MHT CET 2024 · 11 MAY · SHIFT 2Easy

Satellite Energy & Weightlessness

For a satellite moving in an orbit around the earth at height ' hh ' the ratio of kinetic energy to potential energy is

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Answer: (b)

  1. K=GMm2rK = \frac{GMm}{2r}, U=−GMmrU = -\frac{GMm}{r}.
  2. K:∣U∣=1:2K : |U| = 1 : 2.
  3. So the answer is (b) 1:21 : 2.
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