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MHT CET 2023 (10 May, Shift 1) · Satellite Energy & Weightlessness

Satellite Energy & Weightlessness question from MHT CET 2023 (10 May, Shift 1)

Q14MHT CET 2023 · 10 MAY · SHIFT 1Easy

Satellite Energy & Weightlessness

For a satellite orbiting around the earth in a circular orbit, the ratio of potential energy to kinetic energy at same height is

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Answer: (d)

  1. U=−GMmrU = -\frac{GMm}{r}, K=GMm2rK = \frac{GMm}{2r}.
  2. ∣U∣K=2\frac{|U|}{K} = 2.
  3. So the answer is (d) 2.
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