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JEE Main 2021 (20 Jul, Shift 2) · Series LCR Circuit

Series LCR Circuit question from JEE Main 2021 (20 Jul, Shift 2)

Q53JEE Main 2021 · 20 JUL · SHIFT 2Medium

Series LCR Circuit

For a series LCR circuit with R = 100 Ω\Omega, L = 0.5 mH and C = 0.1 pF connected across 220V-\text{-}50 Hz AC supply, the phase angle between current and supplied voltage and the nature of the circuit is:

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Answer: (d)

  1. XL=2π×50×0.5×10−3≈0.16 ΩX_L = 2\pi \times 50 \times 0.5\times10^{-3} \approx 0.16\ \Omega
  2. XC=12π×50×10−13≈3.2×1010 ΩX_C = \dfrac{1}{2\pi \times 50 \times 10^{-13}} \approx 3.2\times10^{10}\ \Omega
  3. XC≫R,XLX_C \gg R, X_L, so tan⁡ϕ=XC−XLR\tan\phi = \dfrac{X_C - X_L}{R} is huge and ϕ≈90∘\phi \approx 90^\circ.
  4. So the answer is (d) ≈90∘\approx 90^\circ, predominantly capacitive circuit.
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