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JEE Main 2015 · Energy in SHM

Energy in SHM question from JEE Main 2015

Q71JEE Main 2015Easy

Energy in SHM

For a simple pendulum, a graph is plotted between its kinetic energy $(KE)$ and potential energy $(PE)$ against its displacement $d.$ Which one of the following represents these correctly? $\left(\textit{graphs are schematic and not drawn to scale}\right)$

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Answer: (d)

$PE = \frac{1}{2}kd^2$ : upward parabola, zero at $d = 0$ .
$KE = \frac{1}{2}k(A^2 - d^2)$ : downward parabola, maximum at $d = 0$ , zero at $d = \pm A$ .
Both are non-negative and cross where $KE = PE$ .
So the answer is (d).

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