Energy in SHM question from NEET 2026

Answer: (c)

1. Pendulum released from extreme: $\theta = \theta_0\cos\omega t$, so $KE = E\sin^2\omega t = \frac{E}{2}(1 - \cos 2\omega t)$.
2. KE is never negative, starts at zero and is zero again at $t = T/2, T$ (the extremes).
3. KE repeats every $T/2$, with maxima at $T/4$ and $3T/4$.
4. So the answer is (c).