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JEE Main 2023 (31 Jan, Shift 2) · Young's Modulus & Elongation

Young's Modulus & Elongation question from JEE Main 2023 (31 Jan, Shift 2)

Q10JEE Main 2023 · 31 JAN · SHIFT 2Easy

Young's Modulus & Elongation

For a solid rod, the Young's modulus of elasticity is 3.2×1011 N m−23.2 \times 10^{11}\text{ N m}^{-2} and density is 8×103 kg m−38 \times 10^{3}\text{ kg m}^{-3}. The velocity of longitudinal wave in the rod will be.

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Answer: (b)

  1. Speed of longitudinal wave in a rod: v=Yρv = \sqrt{\frac{Y}{\rho}}
  2. v=3.2×10118×103=4×107=6.32×103 m s−1v = \sqrt{\frac{3.2 \times 10^{11}}{8 \times 10^{3}}} = \sqrt{4 \times 10^{7}} = 6.32 \times 10^{3}\ \text{m s}^{-1}
  3. So the answer is (b).
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