For a transistor α and β are given as α = (IC)/(IE) and β = (IC)/(IB). Then the correct relation between α and β will be: (a) α = (1-β)/(β) (b) β = (α)/(1-α) (c) αβ = 1 (d) α = (β)/(1-β)

Answer: (b). IE = IB + IC ⇒ IB = IE - IC β = (IC)/(IE - IC) = (α)/(1-α) So the answer is (b).

For a transistor α and β are given as α = (IC)/(IE) and β =… | JEE Main 2021 (27 Aug, Shift 2)

Q63JEE Main 2021 · 27 AUG · SHIFT 2Easy

Junction Transistor

For a transistor $\alpha$ and $\beta$ are given as $\alpha = \frac{I_C}{I_E}$ and $\beta = \frac{I_C}{I_B}$ . Then the correct relation between $\alpha$ and $\beta$ will be:

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Answer: (b)

$I_E = I_B + I_C \Rightarrow I_B = I_E - I_C$
$\beta = \frac{I_C}{I_E - I_C} = \frac{\alpha}{1-\alpha}$
So the answer is (b).

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