For a transistor, current gain (β) = 50. To change the collector current by 350, the base current should be changed by (a) (50/350) (b) (350 - 50) (c) (350 + 50) (d) (350/50)

Answer: (d). β = (Δ IC)/(Δ IB) ⇒ Δ IB = (Δ IC)/(β) Δ IB = 350/50 = 7 μ A So the answer is (d) (350/50)μ A.

For a transistor, current gain (β) = 50. To change the collector… | MHT CET 2024 (15 May, Shift 1)

Q34MHT CET 2024 · 15 MAY · SHIFT 1Easy

Junction Transistor

For a transistor, current gain $(\beta) = 50$ . To change the collector current by $350\,\mu\text{A}$ , the base current should be changed by

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Answer: (d)

$\beta = \dfrac{\Delta I_C}{\Delta I_B} \Rightarrow \Delta I_B = \dfrac{\Delta I_C}{\beta}$
$\Delta I_B = \dfrac{350}{50} = 7\,\mu$ A
So the answer is (d) $\left(\frac{350}{50}\right)\mu$ A.

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