For a transistor, αdc and βdc are the current ratios, then the value of (βdc - αdc)/(αdc × βdc) (a) 2.5 (b) 2 (c) 1.5 (d) 1

Answer: (d). β = (α)/(1-α) ⇒ β - αβ = α ⇒ β - α = αβ (β - α)/(αβ) = 1 So the answer is (d) 1.

For a transistor, αdc and βdc are the current ratios, then the value… | MHT CET 2025 (26 Apr, Shift 2)

Q19MHT CET 2025 · 26 APR · SHIFT 2Easy

Junction Transistor

For a transistor, $\alpha_\text{dc}$ and $\beta_\text{dc}$ are the current ratios, then the value of $\frac{\beta_\text{dc} - \alpha_\text{dc}}{\alpha_\text{dc} \times \beta_\text{dc}}$

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Answer: (d)

$\beta = \dfrac{\alpha}{1-\alpha} \Rightarrow \beta - \alpha\beta = \alpha \Rightarrow \beta - \alpha = \alpha\beta$
$\dfrac{\beta - \alpha}{\alpha\beta} = 1$
So the answer is (d) 1.

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