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NEET 2002 (AIPMT) · Junction Transistor

Junction Transistor question from NEET 2002 (AIPMT)

Q122NEET 2002 · AIPMTEasy

Junction Transistor

For a transistor ICIE\frac{I_C}{I_E} = 0.96, then current gain for common emitter is

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Answer: (d)

  1. α=0.96\alpha = 0.96
  2. β=α1−α=0.960.04=24\beta = \frac{\alpha}{1-\alpha} = \frac{0.96}{0.04} = 24
  3. So the answer is (d) 24.
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