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MHT CET 2021 (24 Sep, Shift 2) · Junction Transistor

Junction Transistor question from MHT CET 2021 (24 Sep, Shift 2)

Q61MHT CET 2021 · 24 SEP · SHIFT 2Easy

Junction Transistor

For a transistor, the current ratio αdc=6970\alpha_\text{dc} = \frac{69}{70}, the current gain βdc\beta_\text{dc} is

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Answer: (b)

  1. β=α1−α\beta = \dfrac{\alpha}{1 - \alpha}
  2. β=69/701/70=69\beta = \dfrac{69/70}{1/70} = 69
  3. So the answer is (b) 69.
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