For a transparent medium, relative permeability and permittivity, μr and εr are 1.0 and 1.44 respectively. The velocity of light in this medium would be, (a) 4.32 × 10⁸ m/s (b) 2.5 × 10⁸ m/s (c) 3 × 10⁸ m/s (d) 2.08 × 10⁸ m/s

Answer: (b). v = (c)/(√(μrεr)) = 3 × 10⁸√(1.0 × 1.44). v = 3 × 10⁸1.2 = 2.5 × 10⁸ m/s. So the answer is (b) 2.5 × 10⁸ m/s.

For a transparent medium, relative permeability and permittivity, μr… | NEET 2019

Q21NEET 2019Easy

Speed of EM Waves in a Medium

For a transparent medium, relative permeability and permittivity, $\mu_r$ and $\varepsilon_r$ are 1.0 and 1.44 respectively. The velocity of light in this medium would be,

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Answer: (b)

$v = \dfrac{c}{\sqrt{\mu_r\varepsilon_r}} = \dfrac{3 \times 10^{8}}{\sqrt{1.0 \times 1.44}}$ .
$v = \dfrac{3 \times 10^{8}}{1.2} = 2.5 \times 10^{8}$ m/s.
So the answer is (b) $2.5 \times 10^{8}$ m/s.

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Speed of EM Waves in a Medium question from NEET 2019

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