For a travelling harmonic wave y(x, t) = 2.0cos 2π(10t - 0.0080x +… | NEET 2026

Q21NEET 2026Easy

Progressive Wave Equation

For a travelling harmonic wave

$y(x, t) = 2.0\cos 2\pi(10t - 0.0080x + 0.35)$ , where $x$ and $y$ are in cm and $t$ in $\text{s}$ . The phase difference between oscillatory motion of two points separated by a distance of 0.5 m is:

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Answer: (b)

$k = 2\pi \times 0.0080\ \text{cm}^{-1}$ ( $x$ in cm).
$\Delta x = 0.5$ m $= 50$ cm
$\Delta\phi = k\,\Delta x = 2\pi \times 0.0080 \times 50 = 0.8\pi$ rad
So the answer is (b) $0.8\pi$ rad.

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