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JEE Main 2021 (16 Mar, Shift 1) · Energy Density & Intensity

Energy Density & Intensity question from JEE Main 2021 (16 Mar, Shift 1)

Q19JEE Main 2021 · 16 MAR · SHIFT 1Easy

Energy Density & Intensity

For an electromagnetic wave travelling in free space, the relation between average energy densities due to electric (Ue) and magnetic (Um) fields is:

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Answer: (a)

$U_e = \tfrac{1}{4}\varepsilon_0 E_0^2$ and $U_m = \dfrac{B_0^2}{4\mu_0} = \dfrac{E_0^2}{4\mu_0 c^2} = \tfrac{1}{4}\varepsilon_0 E_0^2$
So $U_e = U_m$ .
So the answer is (a).

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