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MHT CET 2023 (9 May, Shift 1) · Bohr Model: Orbits, Speed & Angular Momentum

Bohr Model: Orbits, Speed & Angular Momentum question from MHT CET 2023 (9 May, Shift 1)

Q65MHT CET 2023 · 9 MAY · SHIFT 1Easy

Bohr Model: Orbits, Speed & Angular Momentum

For an electron moving in the $n$ th Bohr orbit the deBroglie wavelength of an electron is

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Answer: (d)

Standing-wave condition: $2\pi r = n\lambda$ .
$\lambda = \frac{2\pi r}{n}$
So the answer is (d) $\frac{2\pi r}{n}$ .

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