For angles of projection of a projectile at angle (45o -θ) and (45o + θ), the horizontal range described by the projectile are in the ratio of (a) 2: 1 (b) 1: 1 (c) 2: 3 (d) 1: 2.

Answer: (b). 45° - θ and 45° + θ add up to 90° (complementary). sin (90° - 2θ) = sin (90° + 2θ) = cos 2θ, so the ranges are equal. So the answer is (b) 1: 1.

For angles of projection of a projectile at angle (45o -θ) and (45o +… | NEET 2006 (AIPMT)

Q26NEET 2006 · AIPMTEasy

Comparing Two Projectiles

For angles of projection of a projectile at angle (45o $-\theta$ ) and (45o + $\theta$ ), the horizontal range described by the projectile are in the ratio of

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Answer: (b)

$45^\circ - \theta$ and $45^\circ + \theta$ add up to $90^\circ$ (complementary).
$\sin(90^\circ - 2\theta) = \sin(90^\circ + 2\theta) = \cos 2\theta$ , so the ranges are equal.
So the answer is (b) $1 : 1$ .

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