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MHT CET 2026 (13 Apr, Shift 2) · Transitions, Photon Emission & Excitation

Transitions, Photon Emission & Excitation question from MHT CET 2026 (13 Apr, Shift 2)

Q5MHT CET 2026 · 13 APR · SHIFT 2Medium

Transitions, Photon Emission & Excitation

For hydrogen atom, λ1\lambda_{1} and λ2\lambda_{2} are the wavelengths corresponding to the transitions 11 and 22 respectively as shown in figure. The ratio of λ1\lambda_{1} and λ2\lambda_{2} is x/32x/32. The value of xx is

Figure

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Answer: (b)

  1. From the figure: transition 1 is n=3→1n=3\to1, transition 2 is n=2→1n=2\to1.
  2. 1λ1∝1−19=89\frac{1}{\lambda_1} \propto 1-\frac19 = \frac89; 1λ2∝1−14=34\frac{1}{\lambda_2} \propto 1-\frac14 = \frac34
  3. λ1λ2=3/48/9=2732\frac{\lambda_1}{\lambda_2} = \frac{3/4}{8/9} = \frac{27}{32}
  4. So x=27x = 27, answer (b) 2727.
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