For photoelectric emission from certain metal the cutoff frequency is v. If radiation of frequency 2 ν impinges on the metal plate, the maximum possible velocity of the emitted electron will be (m is the electron mass) (a) √((2hν)/(m)) (b) 2√(hν/m) (c) √((hν)/((2m))) (d) √(hν/m)

Answer: (a). 1/2mvmax² = h(2ν) - hν = hν vmax = √((2hν)/(m)) So the answer is (a) √((2hν)/(m)).

For photoelectric emission from certain metal the cutoff frequency is… | NEET 2013

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Photoelectric Effect: Einstein's Equation

For photoelectric emission from certain metal the cutoff frequency is $v$ . If radiation of frequency 2 $\nu$ impinges on the metal plate, the maximum possible velocity of the emitted electron will be (m is the electron mass)

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Answer: (a)

$\frac{1}{2}mv_{max}^2 = h(2\nu) - h\nu = h\nu$
$v_{max} = \sqrt{\frac{2h\nu}{m}}$
So the answer is (a) $\sqrt{\frac{2h\nu}{m}}$ .

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