For stationary wave, y = 12cos ((π x)/(10))sin (36π t) cm, the distance between a node and the successive antinode is (a) 20 cm (b) 12 cm (c) 10 cm (d) 5 cm

Answer: (d). k = π/10 = (2π)/(λ) ⇒ λ = 20 cm. Node to next antinode = (λ)/(4) = 5 cm. So the answer is (d) 5 cm.

For stationary wave, y = 12cos ((π x)/(10))sin (36π t) cm, the… | MHT CET 2026 (19 Apr, Shift 2)

Q3MHT CET 2026 · 19 APR · SHIFT 2Easy

Stationary Waves & Vibrating Strings

For stationary wave, $y = 12\cos\left(\frac{\pi x}{10}\right)\sin(36\pi t)$ cm, the distance between a node and the successive antinode is

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Answer: (d)

$k = \frac{\pi}{10} = \frac{2\pi}{\lambda} \Rightarrow \lambda = 20\text{ cm}$ .
Node to next antinode $= \frac{\lambda}{4} = 5\text{ cm}$ .
So the answer is (d) $5$ cm.

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