For the circuit given below, the Kirchoff's loop rule for the loop BCDEB is given by the equation (a) -i₂R₂ + E₂ + E₃ + i₃R₁ = 0 (b) -i₂R₂ + E₂ - E₃ + i₃R₁ = 0 (c) i₂R₂ + E₂ - E₃ - i₃R₁ = 0 (d) i₂R₂ + E₂ + E₃ + i₃R₁ = 0

Answer: (c). Go round B→C→D→E→B and add potential changes. B→C along i₂ through R₂: -i₂R₂; C→D through E₂ (+ to −): -E₂. D→E through E₃ (− to +): +E₃; E→B against i₃ through R₁: +i₃R₁. -i₂R₂ - E₂ + E₃ + i₃R₁ = 0, i.e. i₂R₂ + E₂ - E₃ - i₃R₁ = 0. So the answer is (c).

For the circuit given below, the Kirchoff's loop rule for the loop… | NEET 2020 (Phase 2)

Q132NEET 2020 · PHASE 2Easy

Kirchhoff's Laws & Measuring Instruments

For the circuit given below, the Kirchoff's loop rule for the loop $BCDEB$ is given by the equation

Show answer and solution

Answer: (c)

Go round B→C→D→E→B and add potential changes.
B→C along $i_2$ through $R_2$ : $-i_2R_2$ ; C→D through $E_2$ (+ to −): $-E_2$ .
D→E through $E_3$ (− to +): $+E_3$ ; E→B against $i_3$ through $R_1$ : $+i_3R_1$ .
$-i_2R_2 - E_2 + E_3 + i_3R_1 = 0$ , i.e. $i_2R_2 + E_2 - E_3 - i_3R_1 = 0$ . So the answer is (c).

Report a mistake

Kirchhoff's Laws & Measuring Instruments question from NEET 2020 (Phase 2)

More questions on Kirchhoff's Laws & Measuring Instruments