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JEE Main 2021 (20 Jul, Shift 1) · Special Purpose Diodes

Special Purpose Diodes question from JEE Main 2021 (20 Jul, Shift 1)

Q65JEE Main 2021 · 20 JUL · SHIFT 1Medium

Special Purpose Diodes

For the circuit shown below, calculate the value of Iz:

Figure

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Answer: (a)

  1. Is=100−501000=50I_s = \frac{100 - 50}{1000} = 50 mA
  2. IL=502000=25I_L = \frac{50}{2000} = 25 mA
  3. IZ=50−25=25I_Z = 50 - 25 = 25 mA
  4. So the answer is (a) 2525 mA.
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