For the circuit shown in the figure, the current I will be (a) 0.5 A (b) 0.75 A (c) 1 A (d) 1.5 A

Answer: (c). Both cells point the same way, so their emfs add: 2 + 4 = 6 V. Total resistance = 1 + 1 + 4 = 6 Ω. I = 6/6 = 1 A So the answer is (c) 1 A.

For the circuit shown in the figure, the current I will be | NEET 2020 (Phase 2)

Q140NEET 2020 · PHASE 2Medium

Kirchhoff's Laws & Measuring Instruments

For the circuit shown in the figure, the current $I$ will be

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Answer: (c)

Both cells point the same way, so their emfs add: $2 + 4 = 6$ V.
Total resistance $= 1 + 1 + 4 = 6\ \Omega$ .
$I = \frac{6}{6} = 1$ A
So the answer is (c) $1$ A.

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Kirchhoff's Laws & Measuring Instruments question from NEET 2020 (Phase 2)

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