For the diagram shown, the resistance between points A and B when the ideal diode ' D ' is forward biased is ' R₁ ' and that when reverse biased is ' R₂ '. The ratio (R₁)/(R₂) is (a) 2/3 (b) 2/5 (c) 3/2 (d) 5/2

Answer: (b). Forward bias: diode shorted, 40 Ω ∥ 60 Ω: R₁ = (40× 60)/(100) = 24 Ω. Reverse bias: diode branch open, R₂ = 60 Ω. (R₁)/(R₂) = 24/60 = 2/5 So the answer is (b) 2/5.

For the diagram shown, the resistance between points A and B when the… | MHT CET 2024 (9 May, Shift 1)

Q46MHT CET 2024 · 9 MAY · SHIFT 1Medium

P-N Junction Diode

For the diagram shown, the resistance between points A and B when the ideal diode ' $D$ ' is forward biased is ' $R_1$ ' and that when reverse biased is ' $R_2$ '. The ratio $\frac{R_1}{R_2}$ is

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Answer: (b)

Forward bias: diode shorted, $40\ \Omega \parallel 60\ \Omega$ : $R_1 = \dfrac{40\times 60}{100} = 24\ \Omega$ .
Reverse bias: diode branch open, $R_2 = 60\ \Omega$ .
$\dfrac{R_1}{R_2} = \dfrac{24}{60} = \dfrac{2}{5}$
So the answer is (b) $\frac{2}{5}$ .

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