For the diagram shown, the resistances between points A and B when ideal diode D is forward biased is ' R₁ ' and that when reverse biased is ' R₂ '. The ratio R₁: R₂ is (a) 2: 1 (b) 1: 1 (c) 1: 2 (d) 1: 4

Answer: (c). Forward bias: diode shorted, 40 Ω ∥ 40 Ω: R₁ = 20 Ω. Reverse bias: diode branch open, R₂ = 40 Ω. R₁: R₂ = 20: 40 = 1: 2 So the answer is (c) 1:2.

For the diagram shown, the resistances between points A and B when… | MHT CET 2023 (10 May, Shift 2)

Q57MHT CET 2023 · 10 MAY · SHIFT 2Medium

P-N Junction Diode

For the diagram shown, the resistances between points A and B when ideal diode D is forward biased is ' $R_1$ ' and that when reverse biased is ' $R_2$ '. The ratio $R_1 : R_2$ is

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Answer: (c)

Forward bias: diode shorted, $40\ \Omega \parallel 40\ \Omega$ : $R_1 = 20\ \Omega$ .
Reverse bias: diode branch open, $R_2 = 40\ \Omega$ .
$R_1 : R_2 = 20 : 40 = 1 : 2$
So the answer is (c) $1:2$ .

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