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NEET 2023 · Logic Gates

Logic Gates question from NEET 2023

Q94NEET 2023Medium

Logic Gates

For the following logic circuit, the truth table is:

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Answer: (a)

NOT gates give $\bar{A}$ and $\bar{B}$ .
NAND gate: $Y = \overline{\bar{A} \cdot \bar{B}} = A + B$ (De Morgan).
OR table: $Y = 0, 1, 1, 1$ for $AB = 00, 01, 10, 11$ .
So the answer is (a), the first table.

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