For the given circuit, comment on the type of transformer used. (a) Auxiliary transformer (b) Step down transformer (c) Step-up transformer (d) Auto transformer

Answer: (c). Secondary voltage from the load: V₂ = P/iL = (60)/(0.11) ≈ 545 V. V₂ > V₁ = 220 V, so voltage is stepped up. So the answer is (c) step-up transformer.

For the given circuit, comment on the type of transformer used. | JEE Main 2021 (16 Mar, Shift 2)

Q42JEE Main 2021 · 16 MAR · SHIFT 2Easy

AC Generator & Transformer

For the given circuit, comment on the type of transformer used.

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Answer: (c)

Secondary voltage from the load: $V_2 = \dfrac{P}{i_L} = \dfrac{60}{0.11} \approx 545\text{ V}$ .
$V_2 > V_1 = 220\text{ V}$ , so voltage is stepped up.
So the answer is (c) step-up transformer.

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