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JEE Main 2023 (31 Jan, Shift 2) · Capacitors in DC Circuits & RC

Capacitors in DC Circuits & RC question from JEE Main 2023 (31 Jan, Shift 2)

Q23JEE Main 2023 · 31 JAN · SHIFT 2Medium

Capacitors in DC Circuits & RC

For the given circuit, in the steady state, ∣VB−VD∣=|V_B-V_D|= ________ V.

Figure

Numerical answer type. Work it out, then open the answer.

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Answer: 1

  1. Steady state: no current through the capacitor branches, so current from BB to CC goes through the plain wire, making VB=VCV_B = V_C.
  2. Arm AA–DD–CC: I=610+2=0.5 AI = \dfrac{6}{10+2} = 0.5\text{ A}, so VD−VC=0.5×2=1 VV_D - V_C = 0.5\times2 = 1\text{ V}.
  3. ∣VB−VD∣=∣VC−VD∣=1 V|V_B - V_D| = |V_C - V_D| = 1\text{ V}
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