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JEE Main 2019 (12 Jan, Shift 1) · P-V Diagrams & Cyclic Processes

P-V Diagrams & Cyclic Processes question from JEE Main 2019 (12 Jan, Shift 1)

Q64JEE Main 2019 · 12 JAN · SHIFT 1Medium

P-V Diagrams & Cyclic Processes

For the given cyclic process CAB as shown for a gas, the work done is:

Figure

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Answer: (b)

  1. Net work = area of triangle CAB.
  2. Base CA =5−1=4= 5 - 1 = 4 m3^3, height AB =6−1=5= 6 - 1 = 5 Pa.
  3. W=12×4×5=10W = \frac{1}{2} \times 4 \times 5 = 10 J (C to A to B to C is clockwise, so positive).
  4. So the answer is (b) 10 J.
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