For the given reaction, the particle X is ₆C¹¹ → ₅B¹¹ + β⁺ + X (a) neutron (b) anti neutrino (c) neutrino (d) proton

Answer: (c). ₆C¹¹ → ₅B¹¹ + β⁺ is positron decay: p → n + e⁺ + ν. A and Z are already balanced, so X is neutral and massless; lepton number needs a neutrino with the positron. So the answer is (c) neutrino.

For the given reaction, the particle X is ₆C¹¹ → ₅B¹¹ + β⁺ + X | NEET 2000 (AIPMT)

Q28NEET 2000 · AIPMTEasy

Nuclear Reactions & Q-value

For the given reaction, the particle X is

${}_{6}C^{11} \rightarrow {}_{5}B^{11} + \beta^{+} + X$

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Answer: (c)

${}_{6}C^{11} \to {}_{5}B^{11} + \beta^+$ is positron decay: $p \to n + e^+ + \nu$ .
$A$ and $Z$ are already balanced, so $X$ is neutral and massless; lepton number needs a neutrino with the positron.
So the answer is (c) neutrino.

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