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NEET 2020 (Phase 1) · Logic Gates

Logic Gates question from NEET 2020 (Phase 1)

Q138NEET 2020 · PHASE 1Medium

Logic Gates

For the logic circuit shown, the truth table is:

Figure

Figure

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Answer: (d)

  1. NOT gates give Aˉ\bar{A} and Bˉ\bar{B}; the NOR gate gives Y=Aˉ+Bˉ‾Y = \overline{\bar{A} + \bar{B}}.
  2. By De Morgan, Y=A⋅BY = A \cdot B (AND).
  3. AND table: Y=0,0,0,1Y = 0, 0, 0, 1 for AB=00,01,10,11AB = 00, 01, 10, 11.
  4. So the answer is (d), the fourth table.
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