Graphs of Motion question from MHT CET 2024 (11 May, Shift 1)

Answer: (b)

1. Distance = area under the $v$-$t$ graph. Read the time axis as A at $1\text{ s}$, B at $3\text{ s}$, C at $5\text{ s}$, D at $7\text{ s}$ (the last label '4' is a misprint for 7).
2. Total distance = trapezium area $= \frac{1}{2}(2 + 6)\times 10 = 40\text{ m}$
3. Last two seconds (5 s to 7 s): $S_1 = \frac{1}{2}\times 2\times 10 = 10\text{ m}$
4. $\frac{S_1}{S} = \frac{10}{40} = \frac{1}{4}$. So the answer is (b).