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JEE Main 2021 (17 Mar, Shift 1) · Energy in SHM

Energy in SHM question from JEE Main 2021 (17 Mar, Shift 1)

Q57JEE Main 2021 · 17 MAR · SHIFT 1Easy

Energy in SHM

For what value of displacement the kinetic energy and potential energy of a simple harmonic oscillation become equal?

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Answer: (c)

  1. KE=PE⇒12k(A2−x2)=12kx2KE = PE \Rightarrow \frac{1}{2}k(A^2 - x^2) = \frac{1}{2}kx^2
  2. 2x2=A2⇒x=±A22x^2 = A^2 \Rightarrow x = \pm\frac{A}{\sqrt{2}}
  3. So the answer is (c) x=±A2x = \pm\frac{A}{\sqrt{2}}.
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