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NEET 2011 (AIPMT, Prelims) · Work by a Variable Force

Work by a Variable Force question from NEET 2011 (AIPMT, Prelims)

Q21NEET 2011 · AIPMT · PRELIMSEasy

Work by a Variable Force

Force F on a particle moving in a straight line varies with distance d as shown in figure.

The work done on the particle during its displacement of 12 m is

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Answer: (d)

Work = area under the $F$ - $d$ graph.
From 3 m to 7 m (rectangle): $2 \times 4 = 8$ J
From 7 m to 12 m (triangle): $\frac{1}{2} \times 5 \times 2 = 5$ J
Total $W = 8 + 5 = 13$ J, so the answer is (d) 13 J.

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