Combination of Capacitors question from MHT CET 2026 (15 May, Shift 2)

Answer: (c)

1. Label the junctions along the row $n_0, n_1, n_2, n_3, n_4$. The outer loop joins $n_0$ and $n_4$ to $B$; $A$ joins $n_1$ and $n_3$.
2. The two middle capacitors go $A \to n_2 \to A$: both ends at the same potential, so they hold no charge.
3. The end capacitors are each between $A$ and $B$, i.e. in parallel: $C_{AB} = 2C = 2\times16 = 32\ \mu\text{F}$.
4. So the answer is (c) $32$.