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JEE Main 2017 (9 Apr, Shift 1) · Electric Flux & Gauss's Law

Electric Flux & Gauss's Law question from JEE Main 2017 (9 Apr, Shift 1)

Q109JEE Main 2017 · 9 APR · SHIFT 1Easy

Electric Flux & Gauss's Law

Four closed surfaces and corresponding charge distributions are shown below.

Figure

Let the respective electric fluxes through the surfaces be Φ1,Φ2,Φ3\Phi_1, \Phi_2, \Phi_3 and Φ4\Phi_4. Then:

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Answer: (c)

  1. Φ1\Phi_1: qenc=2qq_{enc} = 2q.
  2. Φ2\Phi_2: q+q+q−q=2qq + q + q - q = 2q.
  3. Φ3\Phi_3: q+q=2qq + q = 2q (5q5q is outside).
  4. Φ4\Phi_4: 8q−2q−4q=2q8q - 2q - 4q = 2q (3q3q is outside). All equal 2qε0\dfrac{2q}{\varepsilon_0}.
  5. So the answer is (c).
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