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JEE Main 2021 (24 Feb, Shift 1) · Satellites - Orbital Velocity & Period

Satellites - Orbital Velocity & Period question from JEE Main 2021 (24 Feb, Shift 1)

Q56JEE Main 2021 · 24 FEB · SHIFT 1Difficult

Satellites - Orbital Velocity & Period

Four identical particles of equal masses 1 kg made to move along the circumference of a circle of radius 1 m under the action of their own mutual gravitational attraction. The speed of each particle will be:

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Answer: (d)

  1. For four equal masses on a circle: v=12GMR(1+22)v = \frac{1}{2}\sqrt{\frac{GM}{R}(1+2\sqrt{2})} (net pull GM24R2(1+22)\frac{GM^2}{4R^2}(1+2\sqrt{2})).
  2. Put M=1M = 1 kg, R=1R = 1 m.
  3. So the answer is (d) 12G(1+22)\frac{1}{2}\sqrt{G(1+2\sqrt{2})}.
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