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NEET 2009 (AIPMT) · Moment of Inertia & Radius of Gyration

Moment of Inertia & Radius of Gyration question from NEET 2009 (AIPMT)

Q185NEET 2009 · AIPMTMedium

Moment of Inertia & Radius of Gyration

Four identical thin rods each of mass M and length ll, form a square frame. Moment of inertia of this frame about an axis through the centre of the square and perpendicular to its plane is

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Answer: (d)

  1. Each rod about the square's centre (normal axis): Ml212+M(l2)2=Ml23\frac{Ml^2}{12} + M\left(\frac{l}{2}\right)^2 = \frac{Ml^2}{3}.
  2. Four rods: I=4×Ml23I = 4\times\frac{Ml^2}{3}
  3. So the answer is (d) 43Ml2\frac{4}{3}Ml^2.
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