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MHT CET 2023 (14 May, Shift 2) · Moment of Inertia & Radius of Gyration

Moment of Inertia & Radius of Gyration question from MHT CET 2023 (14 May, Shift 2)

Q92MHT CET 2023 · 14 MAY · SHIFT 2Medium

Moment of Inertia & Radius of Gyration

Four identical uniform solid spheres each of same mass 'MM' and radius 'RR' are placed touching each other as shown in figure, with centres A, B, C, D. IA,IB,ICI_A, I_B, I_C and IDI_D are the moment of inertia of these spheres respectively about an axis passing through centre and perpendicular to the plane. The difference in IAI_A, and IBI_B is

Figure

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Answer: (b)

  1. Centres are 2R2R apart; each sphere's own term is 25MR2\frac{2}{5}MR^2, same in IAI_A and IBI_B.
  2. IA=85MR2+M[(2R)2+(4R)2+(6R)2]=85MR2+56MR2I_A = \frac{8}{5}MR^2 + M[(2R)^2 + (4R)^2 + (6R)^2] = \frac{8}{5}MR^2 + 56MR^2
  3. IB=85MR2+M[(2R)2+(2R)2+(4R)2]=85MR2+24MR2I_B = \frac{8}{5}MR^2 + M[(2R)^2 + (2R)^2 + (4R)^2] = \frac{8}{5}MR^2 + 24MR^2
  4. IA−IB=32MR2I_A - I_B = 32MR^2, so the answer is (b).
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