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MHT CET 2026 (19 May, Shift 2) · Combination of Capacitors

Combination of Capacitors question from MHT CET 2026 (19 May, Shift 2)

Q2MHT CET 2026 · 19 MAY · SHIFT 2Easy

Combination of Capacitors

Four parallel plate capacitors are connected in parallel. Each capacitor has a plate area $\frac{A}{4}$ and the separation between the plates is $d, 2d, 3d$ and $4d$ respectively. The equivalent capacity of the combination is [ $\varepsilon_0 =$ permittivity of free space]

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Answer: (d)

Parallel: add the capacitances $\frac{\varepsilon_0 (A/4)}{d_i}$ .
$C = \frac{A\varepsilon_0}{4d}\left(1 + \frac{1}{2} + \frac{1}{3} + \frac{1}{4}\right) = \frac{A\varepsilon_0}{4d} \cdot \frac{25}{12}$
$C = \frac{25A\varepsilon_0}{48d}$ , so the answer is (d).

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