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Satellites - Orbital Velocity & Period question from JEE Main 2014

Q66JEE Main 2014Difficult

Satellites - Orbital Velocity & Period

Four particles, each of mass MM and equidistant from each other, move along a circle of radius RR under the action of their mutual gravitational attraction. The speed of each particle is:

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Answer: (d)

  1. Adjacent masses 2R\sqrt{2}R apart, opposite one 2R2R away.
  2. Net pull: GM22R2⋅2cos⁡45∘+GM24R2=GM24R2(1+22)\frac{GM^2}{2R^2}\cdot 2\cos 45^\circ + \frac{GM^2}{4R^2} = \frac{GM^2}{4R^2}(1+2\sqrt{2}).
  3. Mv2R=GM24R2(1+22)⇒v=12GMR(1+22)\frac{Mv^2}{R} = \frac{GM^2}{4R^2}(1+2\sqrt{2}) \Rightarrow v = \frac{1}{2}\sqrt{\frac{GM}{R}(1+2\sqrt{2})}.
  4. So the answer is (d).
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