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JEE Main 2020 (6 Sep, Shift 1) · Rotational Kinetic Energy, Work & Power

Rotational Kinetic Energy, Work & Power question from JEE Main 2020 (6 Sep, Shift 1)

Q42JEE Main 2020 · 6 SEP · SHIFT 1Medium

Rotational Kinetic Energy, Work & Power

Four point masses, each of mass m, are fixed at the corners of a square of side ll. The square is rotating with angular frequency ω\omega, about an axis passing through one of the corners of the square and parallel to its diagonal, as shown in the figure. The angular momentum of the square about this axis is:

Figure

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Answer: (a)

axisl/√2l√2 from axisr = 0
  1. Corner on the axis: distance 00.
  2. The two corners on the parallel diagonal are at distance l2\frac{l}{\sqrt{2}} (half the other diagonal).
  3. The opposite corner is at distance l2l\sqrt{2} (full diagonal).
  4. I=2ml22+m(2l2)=3ml2I = 2m\frac{l^2}{2} + m(2l^2) = 3ml^2
  5. L=Iω=3ml2ωL = I\omega = 3ml^2\omega
  6. So the answer is (a) 3ml2ω3ml^2\omega.
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