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MHT CET 2026 (17 Apr, Shift 1) · Moment of Inertia & Radius of Gyration

Moment of Inertia & Radius of Gyration question from MHT CET 2026 (17 Apr, Shift 1)

Q12MHT CET 2026 · 17 APR · SHIFT 1Medium

Moment of Inertia & Radius of Gyration

Four point masses m, 2m, 3m and 4m are kept at the corners A, B, C and D respectively of a square ABCD of side ' $b$ '. The moment of inertia of the system about an axis perpendicular to the plane of the square and passing through the point D is

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Answer: (c)

Distances from D: A and C at $b$ , B at $\sqrt2 b$ ; D itself gives 0.
$I = m b^2 + 3m b^2 + 2m(2b^2)$
$I = 8mb^2$ , so the answer is (c).

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