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JEE Main 2020 (8 Jan, Shift 1) · Wheatstone Bridge & Metre Bridge

Wheatstone Bridge & Metre Bridge question from JEE Main 2020 (8 Jan, Shift 1)

Q61JEE Main 2020 · 8 JAN · SHIFT 1Medium

Wheatstone Bridge & Metre Bridge

Four resistances of 15 $\Omega$ , 12 $\Omega$ , 4 $\Omega$ and 10 $\Omega$ are connected respectively in cyclic order to form Wheatstone's network. The resistance that is to be connected in parallel with the resistance of 10 $\Omega$ to balance the network is _____ $\Omega$ .

Numerical answer type. Work it out, then open the answer.

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Answer: 10

Cyclic order: arms $15, 12, 4, 10$ ; balance needs products of opposite arms equal: $15 \times 4 = 12 \times S'$
$S' = 5\ \Omega$ is needed in place of $10\ \Omega$ .
$\dfrac{10y}{10+y} = 5 \Rightarrow y = 10$
Resistance in parallel $= 10\ \Omega$

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