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MHT CET 2024 (3 May, Shift 2) · Spring Systems

Spring Systems question from MHT CET 2024 (3 May, Shift 2)

Q42MHT CET 2024 · 3 MAY · SHIFT 2Medium

Spring Systems

Frequency of a particle performing S.H.M. is 10 Hz. The particle is suspended from a vertical spring. At the highest point of its oscillation the spring is unstretched. Maximum speed of the particle is $(g = 10\text{ m/s}^2)$

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Answer: (b)

Spring unstretched at the top, so $A = \frac{g}{\omega^2}$ and $v_{max} = \frac{g}{\omega}$ .
$\omega = 2\pi f = 20\pi$ rad/s
$v_{max} = \frac{10}{20\pi} = \frac{1}{2\pi}$ m/s
So the answer is (b).

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