From 18 m height above the ground a ball is dropped from rest. The… | JEE Main 2026 (5 Apr, Shift 1)

Q2JEE Main 2026 · 5 APR · SHIFT 1Easy

Motion Under Gravity

From 18 m height above the ground a ball is dropped from rest. The height above the ground at which the magnitude of velocity equal to the magnitude of acceleration (in the same set of units) due to gravity is ______ m.

(Take $g = 10\text{ m/s}^2$ and neglect the air resistance)

Numerical answer type. Work it out, then open the answer.

Show answer and solution

Answer: 13

Need $v = g = 10$ m/s (numerically).
Distance fallen: $s = \frac{v^2}{2g} = \frac{100}{20} = 5$ m
Height above ground $= 18 - 5 = 13$ m
So the answer is 13 m.

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Motion Under Gravity question from JEE Main 2026 (5 Apr, Shift 1)

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